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0.004=x^2-1.6x-0.8
We move all terms to the left:
0.004-(x^2-1.6x-0.8)=0
We get rid of parentheses
-x^2+1.6x+0.8+0.004=0
We add all the numbers together, and all the variables
-1x^2+1.6x+0.804=0
a = -1; b = 1.6; c = +0.804;
Δ = b2-4ac
Δ = 1.62-4·(-1)·0.804
Δ = 5.776
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1.6)-\sqrt{5.776}}{2*-1}=\frac{-1.6-\sqrt{5.776}}{-2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1.6)+\sqrt{5.776}}{2*-1}=\frac{-1.6+\sqrt{5.776}}{-2} $
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